IS220UCSAH1AK

IS220UCSAH1AK

USD $1081 - $2072 /Piece

Min.Order:1 Piece

Supply Ability:
181 Piece / Pieces per Month
Payment Terms:
T/T
Delivery Detail:
1 days

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Brand Name:
GE
Place of Origin:
China
Model Number:
IS220UCSAH1AK

Temporal Ming sheng automation equipment co., LTD

Business license
Main Products: ABB、GE、MOTOROLA、BENTLY、EMERSON、HIMA、TRICONEX

Product Details

Brand:GE

Type:IS220UCSAH1AK

Origin: the United States

Warranty: 365 days

Colour: new/used

Shipping method: Courier delivery

Module of PLC, DCS, ESD system card, the card is a vibration monitoring system, steam turbine control system module, the advantages of the gas generator spare parts brand: Allen Bradley, BentlyNevada, ABB, Emerson Ovation, Honeywell DCS, Rockwell ICS Triplex, FOXBORO, Schneider PLC, GE Fanuc, Motorola, HIMA, TRICONEX, Prosoft etc. Various kinds of imported industrial parts of our products are widely used in metallurgy, petroleum, glass, aluminum manufacturing, petrochemical industry, coal mine, papermaking, printing, textile printing and dyeing, mechanical, electronic manufacturing, automobile manufacturing, plastic machinery, electric power, water conservancy, water treatment/environmental protection, boiler heating, energy, power transmission and distribution and so on.

BUS ENERGY & POWER NUMERICAL EXAMPLES The energy flows in the drive bus are: • In - Motoring mechanical energy + Motor losses (motor accelerates). • Out - Regenerated mechanical energy – Motor losses (motor decelerates). • Out - Regenerated motor inductive energy (disable or fault). A.4.1 Min. External Bus Capacitance Inductance in AKM motors mated to S200s can be as high as 5 mH (line-to-line). The inductive energy stored in a 5 mH motor at 18 ARMS is calculated as: E winding = 0.75 x Inductance line-to-line x IRMS x IRMS = 0.75 x 0.005 henry x 18 RMS x 18 RMS = 1.2 joules The bus capacitor needed to absorb the regenerated energy (EREGEN) is sized using the general rule that the energy stored in the capacitor be a minimum of 5 * EREGEN. This limits the voltage increase on the bus due to regeneration to 10% of the DC value. Using this general rule to find the minimum bus capacitance for the motor in the above example (for simplicity, ignore that a fraction of regenerated inductive energy is dissipated in the motor): E bus cap = 5 x 1.2 joules = 6 joules E bus cap = 1/2 Cbus x DC voltage x DC voltage Assume the bus DC voltage is 75 volts Cbus = 2 x Ebus cap/(75 V x 75 V) = 2 x 6 joules/(75 V x 75 V) = 2,133 µF The internal S200 bus capacitance is 200 µf, which is less than 10% of the required capacitance for energy absorption. A.4.2 Energy from Acceleration Time The bus supply for a group of S200 drives must have enough total capacitance to handle brief, high-current bus transient flows (positive and negative) a few milliseconds without excessive bus voltage variation. The peak output power of a 6/18 ARMS DC S200 can be as high as 1.5 kW (1.5 kW = 18 ARMS x rt(2) x 60 V (emf + IR)). This is an energy flow of 3 joules for 2 ms or 15 joules for 10 ms. Mechanical energy is estimated by considering the load to be pure inertia and measuring the velocity transition times. A full torque acceleration or deceleration of an inertia load yields a triangle power pulse with an energy (in joules) half of the peak power (in watts) multiplied by the velocity ramp time (in seconds) from zero speed. Monitor the motor acceleration by mapping velocity and torque to DAC monitor pins (J4-14, 15), and then looking at them with a scope. Set DM1Map to VelFB and DM2Map to IFB. See the I/O Setting tab in S200Tools. At a peak power flow to the shaft of 1 kW = (25 A x 40 V EMF), the energy delivered vs. acceleration time is: 5 ms 2.5 joules 10 ms 5.0 joules 15 ms 7.5 joules A.4.3 Capacitor Energy Absorb/Deliver The capacitor energy absorbed or delivered for a 5 V change from a 75 bias is: 3 joules for 8,000 µf 7 joules for 20,000 µf 16 joules for 45,000 µf A.4.4 Bus DC Input Power Bus input power can be estimated by adding motor shaft power and motor resistive winding loss. The shaft power equation is: Shaft power (watt) = Torque (N-m) x Speed (rad/sec) where rad/sec = rpm/60 x 2π

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